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(F)=-F^2+81
We move all terms to the left:
(F)-(-F^2+81)=0
We get rid of parentheses
F^2+F-81=0
a = 1; b = 1; c = -81;
Δ = b2-4ac
Δ = 12-4·1·(-81)
Δ = 325
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{325}=\sqrt{25*13}=\sqrt{25}*\sqrt{13}=5\sqrt{13}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-5\sqrt{13}}{2*1}=\frac{-1-5\sqrt{13}}{2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+5\sqrt{13}}{2*1}=\frac{-1+5\sqrt{13}}{2} $
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